C Language Program To Find Number Of Days Between Two Dates

#include<stdio.h>

#include<math.h>

void main()

{

int day1,mon1,year1,day2,mon2,year2;

int ref,dd1,dd2,i;

clrscr();

printf("\nEnter first day, month, year");

scanf("%d%d%d",&day1,&mon1,&year1);

printf("\nEnter second day,month,year");

scanf("%d%d%d",&day2,&mon2,&year2);

ref = year1;

if(year2<year1)

ref = year2;

dd1=0;

dd1=func1(mon1);

for(i=ref;i<year1;i++)

{

                if(i%4==0)

                dd1+=1;

}

dd1=dd1+day1+(year1-ref)*365;

printf("\nNo. of days of first date fronm the Jan 1 %d= %d",year1,dd1);

/* Count for additional days due to leap years*/

dd2=0;

for(i=ref;i<year2;i++)

{

                if(i%4==0)

                dd2+=1;

}

dd2=func1(mon2)+dd2+day2+((year2-ref)*365);

printf("\nNo. of days from the reference year's first Jan = %d",dd2);

printf("\nTherefore, diff between the two dates is %d",abs(dd2-dd1));

getch();

}

int func1(x)       //x for month y for dd

{  int y=0;

switch(x)

{

case 1: y=0; break;

case 2: y=31; break;

case 3: y=59; break;

case 4: y=90; break;

case 5: y=120;break;

case 6: y=151; break;

case 7: y=181; break;

case 8: y=212; break;

case 9: y=243; break;

case 10:y=273; break;

case 11:y=304; break;

case 12:y=334; break;

default: printf("Error encountered"); exit(1);

}

return(y);

}

Sample Output :
Enter first day, month, year29 7 2009
Enter second day,month,year12 12 2009
No. of days of first date fronm the Jan 1 2009= 210
No. of days from the reference year's first Jan = 346
Therefore, diff between the two dates is 136

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