Interfaces with Operators C#.NET PROGRAM

We can determine whether a particular interface is implemented in a class by using is and as operators. The is operator enables you to check whether one type or class is compatible with another type or class; it returns a Boolean value.
using System;
using System.Collections.Generic;
using System.Text;
namespace ConsoleApplication1
{
    class Program
    {
        interface inter
        {
            bool show();
        }
        interface inter1
        {
            bool display();
        }
        class combineinter : inter
        {
            public bool show()
            {
                System.Console.WriteLine("show() method implemented");
                System.Console.ReadLine();
                return true;
               
            }
        }
      
       
            static void Main(string[] args)
            {
               combineinter interp = new combineinter();
                interp.show();
                inter1 id=interp as inter1;
                if(null!=id)
                {
                    bool ok = id.display();
                    System.Console.WriteLine("Method Implemented");
                    System.Console.ReadLine();
                }
                else
                {
                    System.Console.WriteLine("Method not imlemented");
                    System.Console.ReadLine();
                }
              
            }
        }
    }

OUTPUT