A program to create a linear linked list interactively and print out the list and the total number of items in the list

CODE:

#include<stdio.h>
#include<stdlib.h>
#define NULL 0
struct linked_list
{
int number;
struct linked_list *next;
};
typedef struct linked_list node; /* node type defined */
main()
{
node *head;
void create(node *p);
int count(node *p);
void print(node *p);
head = (node *)malloc(sizeof(node));
create(head);
printf("\n");
printf(head);
printf("\n");
printf("\nNumber of items = %d \n", count(head));
}
void create(node *list)
{
printf("Input a number\n");
printf("(type -999 at end): ");
scanf("%d", &list -> number); /* create current node */
if(list->number == -999)
{
list->
next = NULL;
}
else /*create next node */
{
list->
next = (node *)malloc(sizeof(node));
create(list->next); */ Recursion occurs */
}
return;
}
void print(node *list)
{
if(list->next != NULL)
{
printf("%d-->",list ->number); /* print current item */
if(list->next->next == NULL)
printf("%d", list->next->number);
print(list->next); /* move to next item */
}
return;
}
int count(node *list)
{
if(list->next == NULL)
return (0);
else return(1+ count(list->next));
}

Output:

Input a number
(type -999 to end); 60
Input a number
(type -999 to end); 20
Input a number
(type -999 to end); 10
Input a number
(type -999 to end); 40
Input a number
(type -999 to end); 30
Input a number
(type -999 to end); 50
Input a number
(type -999 to end); -999
60 -->20 -->10 -->40 -->30 -->50 --> -999
Number of items = 6

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